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According to the 2014 U.S. census, $50.8\%$ of the people in the U.S. are females. A simple random sample of $200$ people in the United States were selected.

What is the probability that more than $52\%$ of the people selected were females?

A

$P\left(z > \cfrac { 0.508-0.52 }{ \sqrt { \cfrac { (0.508)(0.492) }{ 200 } } } \right)$

B

$P\left(z > \cfrac { 0.508-0.52 }{ \sqrt { \cfrac { (0.52)(0.48) }{ 200 } } } \right)$

C

$P\left(z > \cfrac { 0.508-0.52 }{ \sqrt { (0.52)(0.48) } } \right)$

D

$P\left(z > \cfrac { 0.52-0.508 }{ \sqrt { \cfrac { (0.508)(0.492) }{ 200 } } } \right)$

E

$P\left(z > \cfrac { 0.52-0.508 }{ \sqrt { \cfrac { (0.52)(0.48) }{ 200 } } } \right)$

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