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Women's heights are approximately normally distributed with a mean of $63.6\text{ inches}$ and a standard deviation of $2.5\text{ inches}$.

Which of the following equations can be used to find the height $x$ in which $18\%$ of the heights fall above?

A

$-0.92=\cfrac { 63.6-x }{ 2.5 }$

B

$-0.92=\cfrac {x-63.6 }{ 2.5 }$

C

$0.18=\cfrac {x-63.6 }{ 2.5 }$

D

$0.92=\cfrac { 63.6-x }{ 2.5 }$

E

$0.92=\cfrac { x-63.6 }{ 2.5 }$

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