A skier goes down a mountain slope. The skier's position on the slope changes with time according to the following formulas:

$x = 0.32 \space t^2 + 1.1 \space t$

$y = - 0.15 \space t^2 - 2.1 \space t + 98$

...where $x$ and $y$ are the skier's horizontal and vertical coordinates with respect to the origin 98 m below the skier's initial position.

All the units are SI.

What is the skier's velocity at time t = 14 s?

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