A skier goes down a mountain slope. The skier's position on the slope changes with time according to the following formulas:
$x = 0.32 \space t^2 + 1.1 \space t$
$y = - 0.15 \space t^2 - 2.1 \space t + 98$
...where $x$ and $y$ are the skier's horizontal and vertical coordinates with respect to the origin 98 m below the skier's initial position.
All the units are SI.
What is the skier's velocity at time t = 14 s?