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A skier of mass $m$ starts from rest at the top of a hill with an angle $\theta$ above the horizontal. The coefficient of kinetic friction between the skier's skis and the snow is $\mu$. If the skier skies straight down the hill without turning, which of the following is the correct expression for the skier's velocity a distance $x$ down the hill? Ignore any effects of static friction.


$v = g(\sin \theta - \mu \cos \theta)$


$v = 2gx(\cos \theta - \mu \sin \theta)$


$v = 2gx(\sin \theta - \mu \cos \theta)$


$v = \sqrt{2gx(\sin \theta - \mu \cos \theta})$

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