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In the game of bridge a player is dealt 13 cards from a standard deck of 52 cards. How many ways are there for a player to get at least 3 cards of each of the 4 suits?

$${13\choose 4}{13\choose 3}^3$$

$${4\choose 1}{13\choose 4}{13\choose 3}^3$$

$${52\choose 13}\cdot 4!\cdot (3!)^3$$

$${52\choose 13}{13\choose 4}{13\choose 3}^3$$

$${52\choose 13}{13\choose 4}{9\choose 3}{6\choose 3}{3\choose 3}$$