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Use the Laplace transform table to find the inverse Laplace transform of:

$$\frac{-5}{(s-3)(s^2+25)}$$

A

$\displaystyle -5 e^{3t} + 5\cos 5t + 3\sin 5t$

B

$\displaystyle e^{3t} + \cos 5t + \sin 5t$

C

$\displaystyle -(5/47) e^{3t} + (5/47) \cos 5t + (3/47) \sin 5t$

D

$\displaystyle (5/34) e^{3t} - (5/34) \cos 5t + (3/34) \sin 5t$;

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