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Joe is given the Laplace transform of a function $f(t)$, which reads $F(s)=\frac{1}{s^2-4}$.

Then, the function $f(t)$ that Joe can recover by taking the inverse Laplace transform is given by

$\cfrac{1}{2}\sin(2t)$

$e^{-4t}$

$\cfrac{1}{4}e^{2t}-\cfrac{1}{4}e^{-2t}$

None of the above