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Consider an ionized helium atom (i.e. a helium atom in which one of the two electrons has been removed). The electric charge of a proton is $1.60\times 10^{-19}\ {\rm C}$.

What is the magnitude of the electric field due to the two protons in the nucleus at the location of the electron, if the electron is separated from the nucleus by a distance of $d=26.5$ pm?


$2.33\times 10^{13}\ {\rm N/C}$


$5.48\times 10^{11}\ {\rm N/C}$


$4.13\times 10^{12}\ {\rm N/C}$


$8.75\times 10^{-11}\ {\rm N/C}$

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