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For benzoic acid, $C_{6}H_{5}CO_{2}H$, the acid ionization constant, $K_{a}$ is $ 6.25 \times 10^{-5}$.

What is the equilibrium constant for the following reaction?

$$C_{6}H_{5}CO_{2}^{-}(aq) + H_{2}O \space \leftrightarrow C_{6}H_{5}CO_{2}H + OH^{-}$$

A

$1.6 \times 10^{4}$

B

$6.25 \times 10^{9}$

C

$1.6 \times 10^{-10}$

D

$6.25 \times 10^{-5}$

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