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A $50\ mL\ $ solution of $0.18 M$ $HOCl$ ($K_a = 3.7\times { 10 }^{ -8 }$) is titrated with $NaOH$.

After $40\ mL\ $ of base has been added, the pH of the solution is $7.7$.

What is the concentration of the $NaOH$ being used for the titration?

A

$0.25 M$

B

$0.20 M$

C

$0.18 M$

D

$0.15 M$

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