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What is the resulting concentration of ${Cl}^{-}(aq)$ if $5.6\text{ mL}$ of $0.15\text{ M}$ $NaCl(aq)$ is added to $12.1\text{ mL}$ of $0.20\text{ M}$ $KCl(aq)$?

A

$0.23\text{ M }{Cl}^{-}(aq)$

B

$0.18\text{ M }{Cl}^{-}(aq)$

C

$0.12\text{ M }{Cl}^{-}(aq)$

D

$0.16\text{ M }{Cl}^{-}(aq)$

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