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Find the perimeter of $\triangle {FBL}$ is simplified radical form.

$3\sqrt {11}+4\sqrt {6}+\sqrt {75}+\sqrt {78}$

$3\sqrt {11}+4\sqrt {6}+5\sqrt {3}$

$3\sqrt {11}+\sqrt {21}+4\sqrt {6}+\sqrt {78}+5\sqrt {3}$

$3\sqrt {11}+4\sqrt {6}+\sqrt {78}+5\sqrt {3}$