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Solve the following equation for $x$:

$$\frac { 1 }{ 3 } x+\frac { 4 }{ 9 } =\frac { 4 }{ 3 } x+\frac { 58 }{ 9 } $$

A

$-6$

B

$-10.8$

C

$172$

D

$-54$

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