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A medical student adds the fluorescent dye bromodeoxyuridine (BRDU) to four cell samples isolated from both healthy and diseased patients. BRDU is a synthetic analog of thymidine. After treating the cells for 48 hours with BRDU, she examines the number of fluorescent cells in each sample. In a healthy tissue, 10% of cells are typically BRDU+ after 48 hours of treatment. She finds the results below.

Figure 1. Percentage of BRDU positive cells in each sample. Error bars represent one standard deviation. Created for Albert.io. Copyright 2017. All rights reserved.

Given the description of BRDU and the results presented in the figure, what might BRDU be a marker for?

A

Cellular necrosis.

B

Cell senescence.

C

Apoptosis.

D

Cell proliferation.

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