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How far is the point $Q=(5,6,7)$ from the plane whose equation is:

$$3x-4y+z-15=0$$

$\frac{17}{\sqrt{26}}$

The point $Q$ is contained in the given plane, so its distance from that plane is zero.

$\frac{\sqrt{17}}{\sqrt{26}}$

$\sqrt{110}$

$\frac{\sqrt{44}}{\sqrt{17}}$