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The half-life of the second-order decomposition of $NOBr(g)$ at 10°C is 165 seconds when the concentration of $NOBr(g)$ is $7.50\times { 10 }^{ -3 } \text{ M}$.

$$2NOBr(g) \rightarrow 2NO(g) + { Br }_{ 2 }(g)$$

What is the concentration of $NOBr(g)$ after 10.0 minutes?

A

$6.03\times { 10 }^{ -4 } \text{ }M$

B

$1.03\times { 10 }^{ -3 } \text{ M}$

C

$1.62 \times { 10 }^{ -3 } \text{ M}$

D

$7.36 \times { 10 }^{ -3 } \text{ M}$

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