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$$4Al + 3O_2→ 2Al_2O_3$$

If 1.08 g of aluminum and 0.99 g of oxygen are available for this reaction, what is the limiting reactant?

A

$Al$

B

$O_2$

C

$Al_2O_3$

D

Mole ratios of reactants are perfectly balanced

E

Insufficient information to determine the answer

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