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Given the figure below, and that $\overline { DB }$ bisects $\angle ABC$, what is the perimeter of $\triangle ABC$? Round your answer to the nearest hundredth.

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$52.55 \text{ ft }$

$48 \text{ ft }$

$40.16 \text{ ft }$

$47.59 \text{ ft }$

$37.59 \text { ft }$