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Find a formula for the nth term of the following sequence:

$$\cfrac{1}{2}, \cfrac{4}{3}, \cfrac{9}{4}, \cfrac{16}{5}...$$

A

${a}_{n}=\cfrac{n+3}{n+1}$

B

${a}_{n}=\cfrac{{n}^{2}}{2n}$

C

${a}_{n}=\cfrac{{n}^{2}}{n+1}$

D

${a}_{n}=\cfrac{{n}!}{n+1}$

E

${a}_{n}=\cfrac{{(n+1)}^{2}}{n}$

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