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For triangle $\text{XYZ}$, if $\text{XY}$ has a length of $2\sqrt{3}$ and $\text{YZ}$ has a length of $2\sqrt{6}$, then find the $\sec(\text{Z})$.

$\sqrt{3}$

$6$

$\cfrac{\sqrt{6}}{3}$

$\cfrac{\sqrt{6}}{2}$

$\cfrac{\sqrt{3}}{3}$