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Using the Chain Rule, find the derivative of:

$$f(x) = \dfrac{1}{x^2-1}$$

$\dfrac{1}{2x}$

$-\dfrac{2x}{(x^2+1)^2}$

$-\dfrac{1}{(x^2+1)^2}$

$-\dfrac{2x+1}{x^4+x^2}$