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Find $y'$ for the function $(x+y)^{1/2}=x^2$

$1/2(x+y)^{-1/2}=2x$

$y'=2(x+y)^{1/2} -1$

$y'=4x(x+y)^{1/2} -1$

$y'=2(x+y)^{1/2} +1$