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Given a $\text{ triangle ABC}$ with $\text{ side AB}=12.17\;cm$ and $\text{ side AC}=9.49\;cm$ and an $\text{ area }=27\;cm^{2}$, find the perimeter of triangle ABC.

Round to the nearest hundredth of a centimeter.

A

$11.41\; cm$

B

$10.77\; cm$

C

$21.24\; cm$

D

$27.49\; cm$

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