Upgrade to access all content for this subject

James Gunnin Created for Albert.io. Copyright 2016. All rights reserved

We are given the triangle above where $\angle{A}={ 40 }^{ \circ }$ and $\angle C={ 65 }^{ \circ }$ and $BD=25$. We are also told that $BD$ is perpendicular to $AC$.

Find the length of $AC$ to the nearest tenth of a unit.

$66.5$

$41.5$

$91.8$

$225.2$