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We are given the triangle above where $\angle{A}={ 40 }^{ \circ }$ and $\angle C={ 65 }^{ \circ }$ and $BD=25$. We are also told that $BD$ is perpendicular to $AC$.

Find the length of $AC$ to the nearest tenth of a unit.

A

$66.5$

B

$41.5$

C

$91.8$

D

$225.2$

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