Upgrade to access all content for this subject

Solve the following equation on the interval $[0, 2\pi)$:

$$\sin^2{\theta}-4\sin{\theta}-5=0$$

This equation is not solvable.

$\cfrac{\pi}{2}$

$\cfrac{3\pi}{2}$

$\cfrac{\pi}{2}, \cfrac{3\pi}{2}$

$0, \pi, \cfrac{\pi}{2}, \cfrac{3\pi}{2}$