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Solve the following equation on the interval $[0, 2\pi)$:

$$4\cos^2{x}-3=0$$

$\cfrac{\pi}{6}, \cfrac{5\pi}{6}$

$\cfrac{\pi}{3}, \cfrac{2\pi}{3}$

$\cfrac{\pi}{3}, \cfrac{2\pi}{3}, \cfrac{4\pi}{3}, \cfrac{5\pi}{3}$

$\cfrac{\pi}{6}, \cfrac{5\pi}{6}, \cfrac{7\pi}{6}, \cfrac{11\pi}{6}$

$\cfrac{2\pi}{3}, \cfrac{4\pi}{3}, \cfrac{7\pi}{6}, \cfrac{11\pi}{6}$