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Given that $\text{ sin}\:\theta=\cfrac { 3 }{ 5 }$ and $\theta$ is in Quadrant II:

Find $\text{ cos}\:\theta$.

A

$ \cfrac { -5 }{ 4 }$

B

$ \cfrac { 5 }{ 3 }$

C

$ \cfrac { -5 }{ 3 }$

D

$ \cfrac { -4 }{ 5 }$

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