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A ship sails from a port (Point ‘A’) at a bearing of ${115}^{°}$ for $250 \text{ km }$. At that time the ship turned and sailed at a bearing of ${208}^{°}$ for another $410\text{ km}$.

How far is the ship from its original port of departure? (Round your answer to the nearest tenth of a kilometer)

A

$468.9\; km $

B

$160.9\; km $

C

$1918.6\; km $

D

$341.1\; km $

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