Why study particle motion calculus? On the AP® exam, free-response questions often ask about the way a particle slides along a track or a car travels on a straight highway. In real-world physics, the same skills predict where satellites, cars, or athletes will be next. This guide explains rectilinear motion, shows how derivatives unlock position, velocity, and acceleration, and offers step-by-step examples that match exam style.
What We Review
Rectilinear Motion Refresher
Rectilinear motion means movement in a straight line. Three linked functions describe it:
- Position: s(t)
- Velocity: v(t)=s'(t)
- Acceleration: a(t)=v'(t)=s''(t)
Typical units are meters (m) and seconds (s). Therefore, velocity is m/s, while acceleration is m/s².
Example #1
Given s(t)=3t^{2}-12t+5 (0 ≤ t ≤ 6), find v(t) and a(t).
Solution
- Differentiate once for velocity.
- v(t)=s'(t)=6t-12
- Differentiate again for acceleration.
- a(t)=v'(t)=6
So the particle moves with a constant acceleration of 6 m/s².
Interpreting Position, Velocity, and Acceleration
Signs matter:
- Positive position → right of the origin
- Negative position → left of the origin
Similarly:
- Positive velocity → moving right
- Negative velocity → moving left
For acceleration:
- Positive acceleration speeds velocity upward.
- Negative acceleration pulls velocity downward.
Linking the signs reveals speeding up versus slowing down:
- Negative velocity + positive acceleration → slowing down (moving left, but braking)
- Positive velocity + negative acceleration → slowing down (moving right, but braking)
- Same sign for v and a → speeding up
Example #2
A particle has v(t)=6-2t and constant a(t)=-2. Identify intervals where it speeds up or slows down.
Solution
- Find when velocity changes sign:
- 6-2t=0\Rightarrow t=3.
- Make a sign chart.
Interval | v | a | Result |
0 < t < 3 | + | – | positive velocity and negative acceleration → slowing down |
t > 3 | – | – | same sign (both negative) → speeding up |
Therefore, the particle slows until 3 s, pauses, then speeds up while moving left.
When Does the Particle Change Direction?
A particle reverses direction where velocity equals zero and the sign of velocity changes. Solve v(t)=0, then test intervals with a sign chart or by graphing v(t).
Example #3
Let s(t)=t^{3}-6t^{2}+9t on 0 ≤ t ≤ 4.
- Find velocity:
- v(t)=s'(t)=3t^{2}-12t+9=3(t-1)(t-3).
- Set v(t)=0: t = 1 s and t = 3 s.
- Sign chart for v(t):
t-range | test point | v-sign |
0–1 | 0.5 | + |
1–3 | 2 | – |
3–4 | 3.5 | + |
Velocity changes sign at 1 s and 3 s, so the particle turns around twice.
Total distance traveled:
- s(0)=0
- s(1)=1-6+9=4
- s(3)=27-54+27=0
- s(4)=64-96+36=4
Distances: |4–0| = 4 m, |0–4| = 4 m, |4–0| = 4 m.Therefore, total distance = 12 m.
Speed vs. Velocity
Speed ignores direction, so \text{speed}=|v(t)|. Many exam errors come from mixing the two. When a problem asks for total distance, integrate the absolute value:
\text{Distance}=\int_{a}^{b}|v(t)|dtPosition, Velocity, and Acceleration Graphs
Graphs make the 4.2 position velocity and acceleration connection visual.
- The slope of a position graph at time t equals v(t).
- The slope of a velocity graph equals a(t).
Therefore, if the velocity graph is rising, acceleration is positive; if it is falling, acceleration is negative.
Calculator-Active Strategies
Graphing calculators shorten work:
- Use nDeriv( to evaluate v(t)=s'(t) or a(t)=v'(t) at single points.
- Use fnInt( for \int |v(t)|dt to find total distance quickly.
- Store s(t) in Y₁, then set a table. Therefore, sign changes become obvious, and tracing reveals turnaround times without algebra.
Quick Reference Chart
Term | Definition / Key Feature |
Rectilinear motion | Movement along a straight line |
s(t) | Position function (m) |
v(t)=s'(t) | Velocity function (m/s) |
a(t)=v'(t)=s''(t) | Acceleration function (m/s²) |
Speed | v(t), always non-negative |
Change of direction | Points where v(t)=0 and velocity sign changes |
Displacement | \int_{a}^{b}v(t)dt (signed area) |
Total distance | \int_{a}^{b}v(t)dt (absolute area) |
Conclusion
Particle motion calculus translates derivatives into real movement. By linking position, velocity, and acceleration, students can spot when a particle speeds up, slows down, or reverses course. Remember the sign rules, practice with graphs, and verify work on a calculator. With these habits, rectilinear motion questions on test day will feel like second nature.
Sharpen Your Skills for AP® Calculus AB-BC
Are you preparing for the AP® Calculus exam? We’ve got you covered! Try our review articles designed to help you confidently tackle real-world math problems. You’ll find everything you need to succeed, from quick tips to detailed strategies. Start exploring now!
- 4.1 Interpreting the Meaning of the Derivative in Context
- 4.3 Rates of Change in Applied Contexts Other Than Motion
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